Problem 6.2.4

 

Draw rectification and stripping lines for a fractionation column that is producing a distillate composition of 91.4 percent when feed is 36 percent in more volatile component.  The feed quality is 1.04 and the equilibrium data can be estimated by a relative volatility of 4.12.  The residue composition is 0.565 percent.

 

Solution:

 

Equilibrium curve (y versus x) can be generated using the relationship: y is equal to alpha x over (one plus (alpha minus one) times x).

Draw a diagonal line (45 degree slope). 

 

Determine the value of the intercept, I, as xD over (R plus one).

Locate point 1 having coordinates (0, I).

Locate point 2 having coordinates (xD, xD).

Join points 1 and 2 and draw a line, called rectification or top operating line (TOL).

Locate point 3 having coordinates (xF, xF).

Locate point 4 having coordinates (xF/q, 0).

Join points 3 and 4 and draw a line, called feed quality (q) line and extend it beyond the equilibrium curve.

Locate the intersection of q-line and rectification line and mark it as point 5.

Locate point 6 having coordinates (xW, xW).

Join point 6 and 5 and draw a line, called stripping or bottom operating line (BOL).

 

Determine the value of the intercept, I, as 0.477.

Locate point 1 having coordinates (0, 0.477).

Locate point 2 having coordinates (0.914, 0.914).

Join points 1 and 2 and obtain rectification line or TOL.

Locate point 3 having coordinates (0.36, 0.36).

Locate point 4 having coordinates (0.346, 0).

Join points 3 and 4 and draw q-line and extend it beyond the equilibrium curve.

Locate the intersection of q-line and rectification line and mark it as point 5.

Locate point 6 having coordinates (0.00565, 0.00565).

Join point 6 and 5 and draw a line, called stripping line or BOL.