Example 11.4: A cooling tower is to cool 20000 lb/h of water from 120 °F to 80 °F.  Inlet air will have a dry bulb temperature of 60 °F and a wet bulb temperature of 50 °F.  A mass transfer coefficient of 80 lb/(h·ft·mol ratio) is expected.  Gy = 800 lb/(h·ft2).  Cross sectional area of the tower is 20 ft2.  Use Merkel design equation to estimate the height of the tower.

 

 

Solution: 

 

Gy = 800 lb/(h·ft2), m = 20000 lb/h, water temperature inlet, t1 = 80 °F,

Water temperature outlet, t2 = 120 °F

Assume specific heat of water, c = 1 Btu/(lb·°F)

Enthalpy of inlet air (60 °F dry bulb, 50 °F wet bulb), h1 = 20.35 - 0.05 = 20.3 Btu/lb

Enthalpy of air at any temperature t in the tower, H = m/(AGy)(t - t1) + h1

Enthalpy of outlet air, h2 = 70.3 Btu/lb

 

 

Temp, t

 

H*/(Btu/lb)

 

H/(Btu/lb)

 

1/(H* - H)

 

80

 

43.7

 

20.3

 

0.0427

 

85

 

49

 

26.55

 

0.0445

 

90

 

56

 

32.8

 

0.0431

 

95

 

63.3

 

39.05

 

0.0412

 

100

 

72

 

45.3

 

0.0375

 

105

 

81.3

 

51.55

 

0.0336

 

110

 

92.3

 

57.8

 

0.029

 

115

 

105

 

64.05

 

0.0244

 

120

 

119.3

 

70.3

 

0.0204

 

 

 

 

 

Mean

 

0.0316

 

Use Equation 11.4 given below to calculate number of transfer units

NTU = (h2 - h1)(1/(H* - H)av) = 1.582

 

Height of transfer unit can be found by using Equation 11.5 given below.

HTU = Gy/Kya = 10

 

Height of Cooling Tower can be calculated through Equation 11.6 given below.

Z = HTU´NTU = 10´1.582 = 15.82 ft