Example
11.4:
A cooling tower is to cool 20000 lb/h of water from 120 °F to 80 °F. Inlet air will have a dry bulb temperature
of 60 °F and a wet
bulb temperature of 50 °F. A mass transfer coefficient of 80 lb/(h·ft·mol ratio) is
expected. Gy = 800
lb/(h·ft2). Cross sectional area of the tower is 20 ft2. Use Merkel design equation to estimate the
height of the tower.
|
|
Solution:
Gy = 800 lb/(h·ft2),
m = 20000 lb/h, water temperature inlet, t1 = 80 °F,
Water
temperature outlet, t2 = 120 °F
Assume
specific heat of water, c = 1 Btu/(lb·°F)
Enthalpy
of inlet air (60 °F dry bulb, 50
°F wet bulb), h1
= 20.35 - 0.05 = 20.3 Btu/lb
Enthalpy
of air at any temperature t in the tower, H = m/(AGy)(t
- t1) + h1
Enthalpy
of outlet air, h2 = 70.3 Btu/lb
|
Temp, t |
H*/(Btu/lb) |
H/(Btu/lb) |
1/(H* - H) |
|
80 |
43.7 |
20.3 |
0.0427 |
|
85 |
49 |
26.55 |
0.0445 |
|
90 |
56 |
32.8 |
0.0431 |
|
95 |
63.3 |
39.05 |
0.0412 |
|
100 |
72 |
45.3 |
0.0375 |
|
105 |
81.3 |
51.55 |
0.0336 |
|
110 |
92.3 |
57.8 |
0.029 |
|
115 |
105 |
64.05 |
0.0244 |
|
120 |
119.3 |
70.3 |
0.0204 |
|
|
|
Mean |
0.0316 |
Use
Equation 11.4 given below to calculate number of transfer units
NTU = (h2
- h1)(1/(H* - H)av) = 1.582
Height
of transfer unit can be found by using Equation 11.5 given below.
HTU = Gy/Kya
= 10
Height
of Cooling Tower can be calculated through Equation 11.6 given below.
Z = HTU´NTU = 10´1.582 = 15.82
ft