Problem 7.2.4

Experimental data (y_A, K) on the retention of oil by liver is given where y_A is mass ratio of oil to solution in the overflow, and K is mass ratio of solution retained to mass of inert (liver). Construct Ponchon-Savarit equilibrium diagram (Y_I versus X_A) for this system.

Solution:

Mass fraction of the inerts, Y_I, is given by I over (A plus S). x_A is mass ratio of oil to solution in the underflow. Its value is the same as y_A, the mass ratio of oil to solution in the overflow. Mass ratio of the solute, X_A, is given by A over (A plus S). This is represented as X_A which is equal to A over (A plus S).

Data point (y_A, K) is converted to (X_A, Y_I) simply as follows: X_A is equal to x_A is also equal to y_A. Y_I is equal to one over K.

Now we can draw a graph between Y_I and X_A. This graph is called Ponchon-Savarit diagram. A vertical line on this curve represents a tie-line (x_A is equal to y_A).