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- Chemical Engineering Review for PE Examination Number of Records: 85Record ID: |83
ID83
Problem No.2613
Equation.
Statement(How much work is required to compress a gas polytropically (index of compression, n = 1.25) from 1 atm and 70 °F to 5 atm. k = 1.6, cP = 4.9675 Btu/(lbmol·°R), cV = 2.98 Btu/(lbmol·°R). Final temperature is 271 °F.)
Ans. (a)(a). 653 BTU/ibmole
Ans. (b)(b). 998 BTU/lbmole
Ans. (c)(c). 1598 BTU/lbmole
Ans. (d)(d). 599 BTU/lbmole
Subtopic
Topicthermo
SubjectMass/Energy Balances and Thermodynamics
| Correct Answer: c | Solution: W = R(T2 - T1)/(1 - n)
W = 1.987(271 - 70)/(1 - 1.25) = -1598 BTU/lbmole