Problem 3.4.3

 

A mixture containing benzene, chlorinated benzene, ethyl benzene, toluene, and xylene is incinerated and the combusted gases are passed through an absorber that absorbs hydrochloric acid, before leaving the stack.  The flow rate from the incinerator is measured at a flow 12,500 dry standard cubic feet per minute.  The oxygen concentration in the stack is 7 percent.   

Data is provided in the first four columns of the table.  Data includes incinerators’ (1) inlet flow rate, (2) outlet flow rate of benzene, chlorobenzene, ethylbenzene, toluene, and xylene.  In addition, stack emission data is provided for hydrochloric acid and particulate matter.  Molecular weight information is listed in the fourth column.  We are required to calculate (1) destruction and removal efficiency (DRE) for all organic compounds, (2) hydrochloric acid removal efficiency of the absorber, and (3) particulate concentration leaving the system in grains per dry standard cubic foot.

 

Solution: 

 

Destruction efficiency is calculated simply by subtracting amount of the component leaving from the amount entering the system and dividing by amount entering the incinerator unit.

For benzene, this value is 2,015 minus 0.537 divided by 2,015 equals 99.9733 percent.  These values are also listed for chlorobenzene, ethylebenzene, toluene, and xylene.

 

There is only one component in the feed that has chlorine atom and that is chloroenzene.  The amount of chlorobenzene destroyed in the incinerator is 1,150 minus 0.109 or 1,149.891 pounds.  This destroyed amount would provide chlorine atom and produce hydrochloric acid in the amount of 1,149.891 times 36.45 divided by 112.5 equals 372.56 pounds.  Please note that 36.5 is the molecular weight of hydrochloric acid and 112.5 of chlorobenzene.  Amount of hydrochloric acid leaving the absorber is reported to be 10.7 pounds.  Thus, hydrochloric acid removal efficiency of the absorber is 372.56 minus 10.7 divided by 372.56 equals 97.128 percent.

 

Finally, concentration of particulate is calculated by multiplying mass emission rate with volumetric flow rate in consistent units:  This translates to 23.4 times 7000 divided by 12,500 divided by 60 equals 0.2184 grains per dry standard cubic foot.  Please note that the number 7000 is a conversion factor between a pound and grains.