Problem 3.5.1

 

Find the moist air properties of air at dry-bulb temperature of 100 degrees F and wet-bulb of 80 degrees F.  Pressure is atmospheric or 29.921 inches of mercury.

 

Solution: 

 

Let us use psychrometric chart for normal temperatures that cover our temperature range. 

 

Locate the state point having dry bulb 100 F (vertical line) and wet-bulb 80 degrees (a line at an angle with negative slope) such that when extended to the saturation curve meets the dry-bulb of 80 degrees F. 

 

Draw a horizontal line to read a humidity value (W) of 0.0175 pounds of water per pound of dry air.

 

Move along the wet bulb line till you reach the saturation temperature curve.  Extend it further to read the enthalpy of saturation from the slanted scale as 43.6 BTUs per pound.  Now, we need to correct by applying the Enthalpy Deviation from the saturation.  Note that these correction curves are broken curves running top to bottom.  Enthalpy deviation is zero when the air completely saturated.  These corrective values are up to negative 0.3 BTU per pound of dry air.  For our situation, this deviation can be read as –0.23 BTU per pound.  So, enthalpy of the moist air is 43.6 plus the correction (negative 0.23) equals 43.37 BTU per pound.

 

Draw a horizontal line to the left to reach the saturation curve.  At the saturation curve, both dry- and wet-bulb temperatures have same value.  In this case, it turns out be 73.2 degrees F.

 

Relative humidity curves are drawn on the psychrometric curve.  These curves are almost parallel to the saturation curve.  For our case, the relative humidity can be interpolated as 42 percent.

 

Volume:  Humid volume is plotted on the psychrometric curve (at angles with negative slope).  These values are 12.5, 13, 13.5, 14, and 14.5 cubic feet per pound of dry air.  For our case, this value is 14.5 cubic feet per pound of dry air.